Blue toruses = 12 protons
Red toruses = 4 nuclear electrons
Atomic number of O (8) = protons (12) - nuclear electrons (4)
Oxygen 12 decomposes by 2 proton emission (from left and right side position) of Oxygen 12 destabilized form through Carbon 10
Carbon 10 undergo a transformation of b+ electron capture (into the central position) of recombinant structure forming Boron 10 stable nucleus.
The other component of the participant photon decomposition, the residual positron emitted.
Click on image for Carbon 10 nuclear structure (half life = 19.290 s)
Light photon modell
Nuclear properties O12 decomposition chain.
There are very few core electron glue in the O12 isotope, so the terminal protons are quickly kicked out by the others. Gluons do not exist.